Because electron fees is indeed brief, these laws and regulations work very well to describe electrostatics getting typical factors

Because electron fees is indeed brief, these laws and regulations work very well to describe electrostatics getting typical factors

ANSWER: The rules you see for instance the one your quotation incorporate merely if charges are going to be looked at as a continuing water which can give alone out on one epidermis, in spite of how high, and possess zero thickness. Obviously, a situation as if you describe, which have 5 excessively electrons is actually not a way eg a liquid and that i would reckon that many techniques from 5-0 so you can 0-5 may be the shipments over a period of time. In principle, the 5 electrons would strategy by themselves so as that for every are given that well away regarding the most other 4 to, however, indeed there would not be an alternative like shipping.

QUESTION: Is it you’ll to suspend an enthusiastic electron via electrostatic levitation inside the a beneficial consistent magnetic community? Of course, if brand new current is actually decreased sufficient and so the electrostatic force to the electron was lower than this new force due to the latest electron’s lbs would the latest electron upcoming experience good ‘fall’ owed to help you the law of gravity?

I am inquiring this simply because I’m questioning in the event the place an excellent positron inside a consistent magnetic profession (within the a vacuum) and you will reducing the voltage to a very brief really worth making sure that new electrostatic force is gloomier compared to weight perform result in good positron to help you together with feel a ‘fall’. And when it did sense a trip it could be determined whether it manage fall up otherwise downwards.

By the inertial bulk After all the fresh new ratio of your push you affect they divided by the the speed, put differently its effectiveness becoming expidited

I am 17 yrs old as well as in the uk going to investigation physics during the college or university for the september and was only interested in learning which since one of our subject areas this season is electrical phenomena and you will we chatted about millikan’s oils lose check out hence featured the same types of suspension system if electrostatic force and you can push on account of the law of gravity was balanced.

Now, we know to help you extraordinary accuracy the inertial size of an excellent positron is equal to the fresh inertial bulk out of an electron

ANSWER: It is always nice to see young folks asking interesting questions. First, I need to correct one thing: everywhere you refer to a “magnetic field” you should say “electric field”; a magnetic field exerts no force on a charge at rest which is what you want to observe, la Millikan. (A more correct way, relativistically, to say this would be that they have equal momenta for equal speeds.) I believe it is true that nobody has ever “weighed” a positron by measuring the force it experiences in a gravitational field. But, if the gravitational mass were different from the inertial mass, this would fly in the face of the theory of general relativity. But, let’s talk about the feasibility of your experiment. The mass of an electron is about 10 -30 kg so its weight would be about 10 -29 N (taking g?10 m/s 2 ). The electron charge is about 1.6×10 -19 C and so the electric field required to levitate an electron would be 10 -29 /1.6×10 -19 ?6×10 -11 V/m. Suppose we use a parallel plate capacitor to create this field. The charge density ? on a plate with field E is about ?=?0E?10 -11 x6x10 -11 =6×10 -22 C/m 2 which would correspond to an electron density on the plates of about 6×10 -22 /1.6×10 -19 ?0.004 electrons/m 2 ! This would correspond to about one electron for every 250 square meters! That would not give a very uniform field would it? There is no such thing as a uniform surface charge density because charges in nature do not comprise a continuous fluid; so really tiny uniform fields are not possible. I did all that just for the fun of it, but there is an even more serious considerationthe earth itself has an electric field near the surface of typically 100 V/m pointing down, so an electron would be repelled upward. To do your experiment you would have to get rid of that field and I do not believe that it would be possible to be assured that you could make the residual field much less than your 6×10 -11 V/m. Back to the drawing board! Keep asking those hard and interesting questions, though, and good luck with your university studies.

Comments for this post are closed.